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A line of a slope of 8 passes through the point (-6,4). What is its equation in point slope form?

Sagot :

gmany

Answer:

[tex]\huge\boxed{y-4=8(x+6)}[/tex]

Step-by-step explanation:

The equation of a line in the point-slope form:

[tex]y-y_1=m(x-x_1)[/tex]

[tex]m-slope\\\\(x_1;\ y_1)-point[/tex]

We have:

[tex]m=8\\\\(-6;\ 4)\to x_1=-6;\ y_1=4[/tex]

Substitute:

[tex]y-4=8(x-(-6))\\\\y-4=8(x+6)[/tex]

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