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in terms of the wavelength of the sound wave, about how far below the open end of the resonance tube is the first resonant position?

Sagot :

The first resonant position below the open end of the resonance tube is; one-quarter of the wavelength

In the event of the first resonant position in a resonance tube, there will be a maximum air displacement which is only one antinode right at the open end where the motion is constrained.

However, there will be no displacement at the closed end which means another one node right at the closed end where air is halted.

This means that the standing wave will have one-quarter of the wavelength in the test tube.

Thus;

L = ¼λ

Read more at; https://brainly.com/question/17086525

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