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2
Technology required. A plane leaves the ground with an elevation angle of 6 degrees.
The plane travels 10 miles horizontally.
a. How high is the plane at the time?
b. What is the distance of the plane's path?
Round answers to the nearest tenths.
How high is the plane at this time?
miles
What is the distance of the plane's path?
miles

2 Technology Required A Plane Leaves The Ground With An Elevation Angle Of 6 Degrees The Plane Travels 10 Miles Horizontally A How High Is The Plane At The Time class=

Sagot :

The height of the plane at that time is 1.1 miles

The distance of the plane's path is 10.1 miles

The situation forms a right angle triangle.

Using trigonometric ratio,

tan 6° = opposite / adjacent

The height of the plane is the opposite side of the triangle. The adjacent

side is the distance travelled horizontally. Therefore,

tan 6° = h / 10

cross multiply

h = 10 tan 6°

h = 10 × 0.10510423526

h = 1.05104235266

height of the plane at that time = 1.1 miles

The distance of the plane path is the hypotenuse of the triangle formed.

Therefore,

c² = a² + b²

c² = 10² + 1.1²

c = √101.21

c = 10.0603180864

c = 10.1  miles

plane's path = 10.1 miles

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