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Sagot :
Answer:
Step-by-step explanation:
From the question, I couldn't really tell what the chart looks like, so I am guessing it looks like this:
Sidewalk 1:
x | y
2 | 17
0 | 5
Sidewalk 2:
x | y
1 | 20
3 | 26
Part a.
Now, we have to write the equation for sidewalk 1 in slope-intercept form.
Slope-intercept form is represented as this: [tex]y=mx+b[/tex], where m is the slope and b is the y-intercept. Because this is true for all values on the line, we can plug in values of the chart for Sidewalk 1.
[tex]17=2m+b\\5=0m+b[/tex]
Subtracting the second equation from the first, we have
[tex]12=2m[/tex], and [tex]m = 6[/tex].
Now, we can just plug 6 back into the first equation to get:
[tex]17=2(6)+b[/tex] to get [tex]17 = 12 + b[/tex], and then [tex]b = 5[/tex].
Now, we can just rewrite slope intercept form for Sidewalk 1 to have
[tex]y=6x+5[/tex].
Part b.
Point-slope form is represented as [tex]y-y_1=m(x-x_1)[/tex], where x and y are the coordinates of one point, and x1 and y1 are the coordinates of another point on the line. Because the chart represented for Sidewalk 2 includes a point, namely [tex](1, 20)[/tex] and [tex](3, 26)[/tex], we can plug this in and solve for the slope:
[tex]26-20=m(3-1)[/tex]
This is it in point-slope form. Because the second part of the question asks us to convert to slope-intercept form, we must solve for the slope, or m.
Expanding, we have [tex]26-20=3m-m[/tex]
Combining like terms, we have [tex]6 = 2m[/tex], and then [tex]3 = m[/tex]. Now, we need to plug a point and the slope back into point-slope form, not needing another point. We choose [tex](1, 20)[/tex], even though [tex](3, 26)[/tex] works just as well.
[tex]y-20=3(x-1)[/tex]
Expanding, we have [tex]y-20=3x-3[/tex]
Adding 20 to both sides, we have [tex]y=3x+17[/tex]
Part c. and d.
We see that both equations do not have the same slope, so then they are not parallel, meaning they don't have no solutions. If they have a solution, we can set them equal to each other.
[tex]3x+17=6x+5[/tex]
Subtracting 3x, we have [tex]17=3x+5[/tex]
Subtracting 5, we have [tex]12 = 3x[/tex]
Dividing by 3, we have [tex]x = 4[/tex].
Because there is no x = x, or anything like that, the solution does not have infinite solutions and therefore has one solution, meaning it is consistent independent.
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