janylamitchell
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(Score for Question 2: of 27 points) 2. Two sidewalks in a park are represented by lines on a coordinate grid. Two points on each of the lines are shown in the tables. Sidewalk 1 х y 2 17 0 5 Sidewalk 2 х у 1 20 3 26 (a) Write the equation for Sidewalk 1 in slope-intercept form. (b) Write the equation for Sidewalk 2 in point-slope form and then convert to slope-intercept form. (c) Is the system of equations consistent independent, coincident, or inconsistent? Explain. a. Note: Review 2.11 Strange Solutions and 5.05 Classifying Systems if you're not sure where to start. (d) Use the substitution or elimination method to solve your system, and explain which one you picked. If the two sidewalks intersect, what are the coordinates of the point of intersection?


PLS HURRRRRRY i need this answer the real one and step by step pls if u dont know it dont try​

Sagot :

CrazyMoosen

Answer:

Step-by-step explanation:

From the question, I couldn't really tell what the chart looks like, so I am guessing it looks like this:

Sidewalk 1:

x  |  y

2  |  17

0  | 5

Sidewalk 2:

x  |  y

1  |  20

3  | 26

Part a.

Now, we have to write the equation for sidewalk 1 in slope-intercept form.

Slope-intercept form is represented as this: [tex]y=mx+b[/tex], where m is the slope and b is the y-intercept. Because this is true for all values on the line, we can plug in values of the chart for Sidewalk 1.

[tex]17=2m+b\\5=0m+b[/tex]

Subtracting the second equation from the first, we have

[tex]12=2m[/tex], and [tex]m = 6[/tex].

Now, we can just plug 6 back into the first equation to get:

[tex]17=2(6)+b[/tex]  to get [tex]17 = 12 + b[/tex], and then [tex]b = 5[/tex].

Now, we can just rewrite slope intercept form for Sidewalk 1 to have

[tex]y=6x+5[/tex].

Part b.

Point-slope form is represented as [tex]y-y_1=m(x-x_1)[/tex], where x and y are the coordinates of one point, and x1 and y1 are the coordinates of another point on the line. Because the chart represented for Sidewalk 2 includes a point, namely [tex](1, 20)[/tex] and [tex](3, 26)[/tex], we can plug this in and solve for the slope:

[tex]26-20=m(3-1)[/tex]

This is it in point-slope form. Because the second part of the question asks us to convert to slope-intercept form, we must solve for the slope, or m.

Expanding, we have [tex]26-20=3m-m[/tex]

Combining like terms, we have [tex]6 = 2m[/tex], and then [tex]3 = m[/tex]. Now, we need to plug a point and the slope back into point-slope form, not needing another point. We choose [tex](1, 20)[/tex], even though [tex](3, 26)[/tex] works just as well.

[tex]y-20=3(x-1)[/tex]

Expanding, we have [tex]y-20=3x-3[/tex]

Adding 20 to both sides, we have [tex]y=3x+17[/tex]

Part c. and d.

We see that both equations do not have the same slope, so then they are not parallel, meaning they don't have no solutions. If they have a solution, we can set them equal to each other.

[tex]3x+17=6x+5[/tex]

Subtracting 3x, we have [tex]17=3x+5[/tex]

Subtracting 5, we have [tex]12 = 3x[/tex]

Dividing by 3, we have [tex]x = 4[/tex].

Because there is no x = x, or anything like that, the solution does not have infinite solutions and therefore has one solution, meaning it is consistent independent.

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