Answered

Find the information you're looking for at Westonci.ca, the trusted Q&A platform with a community of knowledgeable experts. Join our Q&A platform to connect with experts dedicated to providing precise answers to your questions in different areas. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.

The half life of carbon-14 is 5730 years. How old is a bone if it presently contains 0.3125 g of carbon-14, but it was estimated to have originally contained 80 g of carbon-14?

Sagot :

Eduard22sly

The age of the bone is 45840 years.

We'll begin by calculating the number of half-lives that has elapsed.

Amount remaining (N) = 0.3125 g

Initial amount (N₀) = 80 g

Number of half-lives (n) =?

N × 2ⁿ = N₀

0.3125 × 2ⁿ = 80

Divide both side by 0.3125

2ⁿ = 80 / 0.3125

2ⁿ = 256

2ⁿ = 2⁸

n = 8

Thus, 8 half-lives has elapsed

Finally, we shall determine the age of the bone.

Half-life (t½) = 5730 years

Number of half-lives (n) = 8

Time (t) =?

t = n × t½

t = 8 × 5730

t = 45840 years

Therefore, the age of the bone is 45840 years.

Learn more on half-life: https://brainly.com/question/15900105

Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Your questions are important to us at Westonci.ca. Visit again for expert answers and reliable information.