wiiusuperbros
Answered

At Westonci.ca, we connect you with the best answers from a community of experienced and knowledgeable individuals. Explore in-depth answers to your questions from a knowledgeable community of experts across different fields. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.

What is the freezing point, in Celsius, of a sucrose-water solution containing 2.23g sucrose per 100g water. The molal freezing point depression constant for water is 1.86oC/m.

Sagot :

pstnonsonjoku

The freezing point of the solution is - 0.12 oC.

We know that;

ΔT = K m i

ΔT = Freezing point depression

K = Freezing constant

m = molality

i = Van't Hoff factor

Number of moles of sucrose= 2.23g/342 g/mol = 0.0065 moles

Mass of solvent in Kg = 0.1 Kg

Molality of the solution = 0.0065 moles/ 0.1 Kg = 0.065 m

Now;

ΔT = 1.86 oC/m × 0.065 m × 1

ΔT = 0.12 oC

Freezing point of pure water = 0 oC

Freezing point of solution =  0 oC -  0.12 oC = - 0.12 oC

Learn more: https://brainly.com/question/2292439

We hope this was helpful. Please come back whenever you need more information or answers to your queries. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Thank you for using Westonci.ca. Come back for more in-depth answers to all your queries.