wiiusuperbros
Answered

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What is the freezing point, in Celsius, of a sucrose-water solution containing 2.23g sucrose per 100g water. The molal freezing point depression constant for water is 1.86oC/m.

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The freezing point of the solution is - 0.12 oC.

We know that;

ΔT = K m i

ΔT = Freezing point depression

K = Freezing constant

m = molality

i = Van't Hoff factor

Number of moles of sucrose= 2.23g/342 g/mol = 0.0065 moles

Mass of solvent in Kg = 0.1 Kg

Molality of the solution = 0.0065 moles/ 0.1 Kg = 0.065 m

Now;

ΔT = 1.86 oC/m × 0.065 m × 1

ΔT = 0.12 oC

Freezing point of pure water = 0 oC

Freezing point of solution =  0 oC -  0.12 oC = - 0.12 oC

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