SophiaSuhel
Answered

Discover a wealth of knowledge at Westonci.ca, where experts provide answers to your most pressing questions. Join our Q&A platform and connect with professionals ready to provide precise answers to your questions in various areas. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.

ΔABC is an isosceles triangle with AB = AC, D is the midpoint of BC and
AD is joined. Prove that ΔABD ≅ ΔACD.
I kinda have a problem with triangles and congruency....little help please ?

Sagot :

doudoupeihe

Step-by-step explanation:

Okay, so the triangle would look something like this:

see the image attached

Since AB=AC, which is given; <ABD = <ACD, because they are the angles opposite from the congruent sides of the isosceles triangle; and <ADB=<ADC, as AD is the bisector*; ΔABD ≅ ΔACD using SAA/AAS (side-angle-angle) congruencey.

*If the bisector of an angle in a triangle meets the opposite side at its midpoint, then the triangle is isosceles, and vice versa

(I haven't done Geometry in a while so I hope that's correct :) )

View image doudoupeihe
Thank you for visiting our platform. We hope you found the answers you were looking for. Come back anytime you need more information. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. We're dedicated to helping you find the answers you need at Westonci.ca. Don't hesitate to return for more.