Westonci.ca is the ultimate Q&A platform, offering detailed and reliable answers from a knowledgeable community. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.
Sagot :
Step-by-step explanation:
polynomial identities means equations where the left and the right side are always identical (no matter what values we use for the variables).
so,
A is not.
(x + 2)³ = x³ + 8
(x+2)(x+2)(x+2) = x³ + 8
(x² + 4x + 4)(x+2) = x³ + 8
x³ + 4x² + 4x + 2x² + 8x + 8 = x³ + 8
x³ + 6x² + 10x + 8 is definitely not generally the same as x³ + 8
B is not.
x⁶ + x = (x-1)(x⁵ + x⁴ + x³ + x² + x)
x⁶ + x = x⁶ + x⁵ + x⁴ + x³ + x² - x⁵ - x⁴ - x³ - x² - x
x⁶ + x = x⁶ - x
that is definitely not generally equal.
C is an identity
(x² - 1)(x⁴ + x² + 1) = x⁶ - 1
x⁶ + x⁴ + x² - x⁴ - x² - 1 = x⁶ - 1
x⁶ - 1 = x⁶ - 1
yes, identical.
D is not.
(x+1)⁴ = x⁴ + x³ + x² + x + 1
(x+1)²(x+1)² = x⁴ + x³ + x² + x + 1
(x²+2x+1)² = x⁴ + x³ + x² + x + 1
x⁴ + 2x³ + x² + 2x³ + 4x² + 2x + x² + 2x + 1 =
x⁴ + 4x³ + 6x² + 4x + 1
that is definitely not generally the same as
x⁴ + x³ + x² + x + 1
E is an identity
(x+1)(x⁴ - x³ + x² - x + 1) = x⁵ + 1
x⁵ - x⁴ + x³ - x² + x + x⁴ - x³ + x² - x + 1 =
x⁵ + 1 = x⁵ + 1
yes, identical.
F is an identity
(x³-1)(x³+1) = x⁶ - 1
x⁶ + x³ - x³ - 1 = x⁶ - 1
x⁶ - 1 = x⁶ - 1
yes, identical.
We hope this was helpful. Please come back whenever you need more information or answers to your queries. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Get the answers you need at Westonci.ca. Stay informed with our latest expert advice.