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Write the equation of a line that
passes through the following points
:
Point 2: (0,-8)
Point 1: (-3,0)


Sagot :

Answer:

[tex]y = \frac{-8}{3}x - 8[/tex]

Step-by-step explanation:

Solving for the equation of the line with two points:

Let's remind ourself of the slope - intercept formula:    [tex]y = mx + b[/tex]

We first have to find the slope of the line. This is found by using the formula :

[tex]\frac{y_1 - y_2}{x_1 - x_2}[/tex]

We have to find the change in y (Δy) and divide it by the change in x (Δx)

We then have to plug in a coordinate given to us, and use the point's x and y value to find the y - intercept

Step 1: Slope

Let's use the slope formula

[tex]\frac{0 - (-8)}{-3 - 0} = \frac{8}{-3}[/tex]

Slope = -8/3

Step 2: Y - Intercept

To find the y - intercept, we'll update our slope - intercept formula with the slope, and plugin a point. Let's use (-3,0)

[tex]y = \frac{-8}{3}x + b[/tex]

[tex]0 = \frac{-8}{3}(-3) + b[/tex]

[tex]0 = \frac{24}{3} + b[/tex]

[tex]0 = 8 + b[/tex]

[tex]b = -8[/tex]

Step 3: Equation

Let's input our slope and y - intercept to the equation     [tex]y = mx + b[/tex]

Slope = -8/3

Y - Intercept = -8

Equation:    [tex]y = \frac{-8}{3}x - 8[/tex]

-Chetan K

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