Answered

Get the answers you need at Westonci.ca, where our expert community is dedicated to providing you with accurate information. Get quick and reliable solutions to your questions from knowledgeable professionals on our comprehensive Q&A platform. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.

gina has 480 yards of fencing to enclose a rectangular area. Find the dimensions of the rectangle that maximize the enclosed area. What is the maximum​ area?

Sagot :

evgeniylevi

Answer:

14400 [yards²].

Step-by-step explanation:

all the details are in the attached picture; answer is marked with orange colour.

note, the suggested way of solution is not the shortest one, modify the design according Your local requirements.

P.S. ∡ means 'if', ⇒ means 'then'.

View image evgeniylevi
mhanifa

Answer:

  • 14400 yd²

Step-by-step explanation:

Fencing is the perimeter of rectangle:

  • P = 2(l + w) = 480

The sum of dimensions is:

  • l + w = 240 yd

The area is the product of two dimensions:

  • A = lw
  • A = l(240 - l) = 240l - l²

This a quadratic relationship and the maximum value is obtained at vertex.

The vertex is the point:

  • l = -b/2a = -240/ -2 = 120

It means both l and w have same length of 120 yd

The area is:

  • A = 120*120 = 14400 yd²
Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.