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[tex] \frac{x - 3}{5} = \frac{x + 5}{3} [/tex]
Find the value of x​


Sagot :

[tex]\dfrac{x-3}5 = \dfrac{x+5}3 \\\\\implies 3(x-3) = 5(x+5)\\\\\implies 3x - 9 = 5x +25\\\\\implies 5x -3x +25 +9 =0\\\\\implies 2x +34 =0\\\\\implies 2x = -34 \\\\\implies x = -\dfrac{34}2 =-17[/tex]

[tex]\sf \longmapsto \: \dfrac{x - 3}{5} = \dfrac{ x + 5}{3} [/tex]

[tex]\sf \longmapsto \: 3(x - 3) = 5(x + 5)[/tex]

[tex]\sf \longmapsto \: 3x - 9 = 5x + 25[/tex]

[tex]\sf \longmapsto3x - 5x = 25 + 9[/tex]

[tex]\sf \longmapsto - 2x = 34[/tex]

[tex]\sf \longmapsto \: x = \dfrac{34}{ - 2} [/tex]

[tex]\sf \longmapsto \: x =- \cancel \dfrac{34}{ 2} [/tex]

[tex]\sf \longmapsto \: x = - 17[/tex]

[tex]\boxed{\Rightarrow\: x = - 17}[/tex]