christian7533
Answered

Welcome to Westonci.ca, the place where your questions are answered by a community of knowledgeable contributors. Ask your questions and receive detailed answers from professionals with extensive experience in various fields. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.

What is the distance from point (– 1, 3) to the line 3x – 4y = 10?​

Sagot :

Answer:

5 units

Step-by-step explanation:

The distance from a point (m, n ) to the line Ax + By + C = 0 is given by

d = [tex]\frac{|Am+Bn+C|}{\sqrt{A^2+B^2} }[/tex]

For the point (- 1, 3 ) , with m = - 1 and n = 3

3x - 4y = 10 ( subtract 10 from both sides )

3x - 4y - 10 = 0

with A = 3 , B = - 4 , C = - 10

d = [tex]\frac{|3(-1)+(-4)3-10|}{\sqrt{3^2+(-4)^2} }[/tex]

   = [tex]\frac{|-3-12-10|}{9+16}[/tex]

   = [tex]\frac{|-25|}{\sqrt{25} }[/tex]

    = [tex]\frac{25}{5}[/tex]

     = 5

Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Thank you for visiting Westonci.ca, your go-to source for reliable answers. Come back soon for more expert insights.