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Sagot :
Two adjacent sides are given by 3x-6 and x+14.
Now, because its a rhombus all sides of it are
equal.
By the problem,
3x-6=X+14
2x=20
X=10
Perimeter of rhombus- 4a (a=side of rhombus)
4*10=40 units
Now, because its a rhombus all sides of it are
equal.
By the problem,
3x-6=X+14
2x=20
X=10
Perimeter of rhombus- 4a (a=side of rhombus)
4*10=40 units
Given that:
The consecutive sides of a rhombus are 3x-6 and x+14 .
We know that
all sides are equal in a rhombus
⇛ 3x-6 = x+14
⇛ 3x-x = 14+6
⇛ 2x = 20
⇛ x = 20/2
⇛ x = 10
Now,
3x-6 = 3(10)-6 = 30-6 = 24
Length of the side = 24 units
Now,
Perimeter of a rhombus = 4×side
⇛ P = 4×24 units
P = 96 units
Answer:-The perimeter of the given rhombus is 96 units.
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