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What is the equation of this trend line?

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What Is The Equation Of This Trend Line Enter Your Answers By Filling In The Boxes class=

Sagot :

Answer:

k = - 2j + 28

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]

with (x₁, y₁ ) = (14, 0 ) and (x₂, y₂ ) = (0, 28 ) ← 2 points on the line

m = [tex]\frac{28-0}{0-14}[/tex] = [tex]\frac{28}{-14}[/tex] = - 2

The line crosses the y- axis at (0, 28 ) ⇒ c = 28

In this graph the y- axis is the k- axis and the x- axis the j- axis , then

k = - 2j + 28 ← equation of line

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