Answered

Welcome to Westonci.ca, the place where your questions are answered by a community of knowledgeable contributors. Get the answers you need quickly and accurately from a dedicated community of experts on our Q&A platform. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.

Your parents put in fencing around the walkway for safety. If 110 feet of fencing is used, what are the dimensions of the pool?

Sagot :

raphealnwobi

The dimension of the pool has a length of 27.5 feet and width of 27.5 feet.

Let x represent the length of the pool and y represent the width of the pool

Perimeter = 2(length + width)

110 = 2(x + y)

x + y = 55

y = 55 - x

Area (A) = length * width

A = x * y

A = x(55 - x)

A = 55x - x²

The maximum area is at dA/dx = 0, hence:

dA/dx = 55 - 2x

0 = 55 - 2x

2x = 55

x = 27.5 feet

y = 55 - x = 55 - 27.5

y = 27.5 feet

The dimension of the pool has a length of 27.5 feet and width of 27.5 feet.

Find out more at: https://brainly.com/question/11906003

Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. We hope this was helpful. Please come back whenever you need more information or answers to your queries. We're glad you visited Westonci.ca. Return anytime for updated answers from our knowledgeable team.