Discover the answers you need at Westonci.ca, a dynamic Q&A platform where knowledge is shared freely by a community of experts. Discover detailed solutions to your questions from a wide network of experts on our comprehensive Q&A platform. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.
Sagot :
The result will always be 4 because the first four lines of code gets a number [tex]k+4[/tex], where [tex]k=\frac{\text{secret num}}{2}[/tex], and the last line subtracts [tex]4[/tex] from [tex]k+4[/tex].. therefore leaving us with the value [tex]4[/tex].
The effect of each line is explained below:
secret_num = 10
Assigns the value 10 to secret_num
temp = secret_num + 8
Stores the value 18 in temp
temp = temp * 2
Stores the value 36 in temp
temp = temp / 4
Stores the value 9 in temp
answer = temp - secret_num / 2
Stores the value 4 in answer
If the reasoning were done algebraically, we would have
[tex](((\text{secret num} + 8)\times 2)/4)-\text{secret num}/2\\[/tex]
Where the bracket nesting reflects the sequence of operations that led to the final answer in the code
Writing it mathematically, and simplifying
[tex]\frac{2(\text{secret num} + 8)}{4}-\frac{\text{secret num}}{2}\\\\=\frac{2\times\text{secret num} + 16}{4}-\frac{\text{secret num}}{2}\\\\=\frac{\text{secret num}}{2}+4-\frac{\text{secret num}}{2}\\\\=\frac{\text{secret num}}{2}-\frac{\text{secret num}}{2}+4\\\\=4[/tex]
We see that at the end, no matter what the value of secret_num was, the secret_num term still cancels out, leaving us with 4.
Learn more about Arithmetic operations here: https://brainly.com/question/5973382
We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Discover more at Westonci.ca. Return for the latest expert answers and updates on various topics.