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2 A boy of mass 50 kg runs up a hill of vertical height
300 m in 20 minutes Calculate: a) the average vertical force he uses to lift
himself up the hillside b) the work he does climbing the hill c) his average power

Sagot :

temdan2001

The Vertical force is the same as his weight. By using the formula of work done and power, the correct answers are:

a.) 490N

b.) 147 KJ

c.) 122.5 W

Given that a boy of mass 50 kg runs up a hill of vertical height

300 m in 20 minutes.

a) The average vertical force he uses to lift himself up the hillside will be his normal reaction force (N) on the hill

N = mg

N = 50 x 9.8

N = 490N

b) the work he does climbing the hill will be

W = F x S

W = 490 x 300

W = 147000 Joules

W = 147 KJ

c) his average power will be

P = W/t

First convert the time from minutes to seconds

20 minutes = 20 x 60 = 1200 seconds

Substitute the time t and the work done W into the power formula

P = 147000/1200

P = 122.5 Watts

Learn more here: https://brainly.com/question/21854305

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