The quadratic equation is given by:
y = 3x² + 10x - 8
The standard equation of a parabola is given by:
y = ax² + bx + c
Where a, b, c are constants
At point (4, 80):
80 = a(4)² + b(4) + c
16a + 4b + c = 80 (1)
At point (-3, -11):
-11 = a(-3)² + b(-3) + c
9a - 3b + c = -11 (2)
At point (-1, -15):
-15 = a(-1)² + b(-1) + c
a - b + c = -15 (3)
Solving equations 1, 2 and 3 simultaneously gives:
a = 3, b = 10, c = -8
Therefore the quadratic equation becomes:
y = 3x² + 10x - 8
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