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Sagot :
The acceleration of the box is 0.025 m/s²
We'll begin by calculating the the frictional force
Coefficient of kinetic friction (μ) = 0.21
Mass (m) = 8 Kg
Acceleration due to gravity (g) = 10 m/s²
Normal reaction (N) = mg = 8 × 10 = 80 N
Frictional force (Fբ) =?
Fբ = μN
Fբ = 0.21 × 80
Fբ = 16.8 N
- Next, we shall determine the net force acting on the box
Frictional force (Fբ) = 16.8 N
Force (F) = 17 N
Net force (Fₙ) =?
Fₙ = F – Fբ
Fₙ = 17 – 16.8
Fₙ = 0.2 N
- Finally, we shall determine the acceleration of the box
Mass (m) = 8 Kg
Net force (Fₙ) = 0.2 N
Acceleration (a) =?
a = Fₙ / m
a = 0.2 / 8
a = 0.025 m/s²
Therefore, the acceleration of the box is 0.025 m/s²
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