Answered

Welcome to Westonci.ca, your go-to destination for finding answers to all your questions. Join our expert community today! Discover reliable solutions to your questions from a wide network of experts on our comprehensive Q&A platform. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.

The coefficient of kinetic friction is 0.21, for a 8 kg block on the floor. It is being pulled by a 17 N force, what is the acceleration of the box?

Sagot :

Eduard22sly

The acceleration of the box is 0.025 m/s²

We'll begin by calculating the the frictional force

Coefficient of kinetic friction (μ) = 0.21

Mass (m) = 8 Kg

Acceleration due to gravity (g) = 10 m/s²

Normal reaction (N) = mg = 8 × 10 = 80 N

Frictional force (Fբ) =?

Fբ = μN

Fբ = 0.21 × 80

Fբ = 16.8 N

  • Next, we shall determine the net force acting on the box

Frictional force (Fբ) = 16.8 N

Force (F) = 17 N

Net force (Fₙ) =?

Fₙ = F – Fբ

Fₙ = 17 – 16.8

Fₙ = 0.2 N

  • Finally, we shall determine the acceleration of the box

Mass (m) = 8 Kg

Net force (Fₙ) = 0.2 N

Acceleration (a) =?

a = Fₙ / m

a = 0.2 / 8

a = 0.025 m/s²

Therefore, the acceleration of the box is 0.025 m/s²

Learn more: https://brainly.com/question/364384

We appreciate your visit. Hopefully, the answers you found were beneficial. Don't hesitate to come back for more information. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Westonci.ca is your go-to source for reliable answers. Return soon for more expert insights.