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The sum of the digits of a two digit number is 14. When the digits are reversed, the new number is 36 less than the original number. Find the original number. Check your answer.

Sagot :

mikaiwills28

Answer:Here is the algebraic solution: T is the tens digit O is the ones digit T+O = 14 So

Step-by-step explanation:O = 14 - T <---- this is the first equation

The original number is 10*T + O

If the digits are reversed the original number is increased by 18.

The number if the digits are reversed is:

10*O + T = 10*T + O + 18

10*(14-T) + T = 10*T + (14-T) + 18 <--- substitutes O with 14-T per first equation above in bold

140 - 10T + T = 10T + 14 - T + 18 <--- distributive left side

140 - 9T = 9T + 32

140 = 9T + 9T + 32

140 - 32 = 9T + 9T

108 = 18T

108/18 = T

T= 6

THe tens digit is 6.

The ones digit must be 8.

Reversing 86 - 68 = 18

The original number is 68.

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