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Sagot :
The force exerted by the laser beam on a completely absorbing target is [tex]3.5 \times 10^{-6} \ N[/tex].
The given parameters;
- power of the laser light, P = 1050 W
- wavelength of the emitted light, λ = 10 μm
The speed of the emitted laser light is given as;
v = 3 x 10⁸ m/s
The force exerted by the laser beam on a completely absorbing target is calculated as follows;
P = Fv
[tex]F = \frac{P}{v} \\\\F = \frac{1050}{3\times 10^8} \\\\F = 3.5 \times 10^{-6} \ N[/tex]
Thus, the force exerted by the laser beam on a completely absorbing target is [tex]3.5 \times 10^{-6} \ N[/tex].
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