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On a coordinate plane, an exponential function approached y = 0 in quadrant 2 and increases into quadrant 1. It crosses the x-axis at (0, 2). What is the initial value of the exponential function shown on the graph? 0 1 2 4.

Sagot :

MrRoyal

The initial value of an exponential function is the y-intercept of the function

The initial value of the exponential function is 2.

From the question, we understand that the exponential function crosses the y-axis at point (0,2)

This means that, the value of y when x = 0 is 2

In other words, the y-intercept is 2.

Hence, the initial value of the exponential function is 2.

Read more about exponential functions at:

https://brainly.com/question/2456547

Answer:

the answer is C

Step-by-step explanation:

just took the test

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