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Sagot :
From the information in the question, the velocity of the particle is 24 ms-1.
Let us recall that the velocity of a body is obtained as the first derivative of distance covered with respect to time. Hence;
ds/dt = v
Now, we have to differentiate (t^3- 3t^2 + 2)m with respect to t and we have;
d(t^3- 3t^2 + 2)m/dt = 3t^2 - 6t
Now at t= 4s, the velocity of the particle is;
3(4)^2 - 6(4) = 24 m/s
The acceleration of the particle is the second derivative of distance with respect to time;
d^2s/dt^2 = d^2 3t^2 - 6t/dt^2 = 6t
Substituting t = 4s
a = 24 ms-2
Learn more: https://brainly.com/question/24486060
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