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What is the vertex of the parabola y=-x^2+4x-5

Vertex= ( , )

Sagot :

Answer:

Ans: (-2, -9)

Explanation:

x-coordinate of the vertex:

x

=

(

b

2

a

)

=−42=−2y-coodinate of vertex: y=f(−2)=(−2)2+4(−2)−5=4−8−=−9

Step-by-step explanation: