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If there is direct variation and y= 27 when x = 4, find Y
when x = 12

Sagot :

The value of y when x = 12 given the direct variation of y = 27 when x = 4 is 81

Given:

y = 27

x = 4

y = k × x

where,

k = constant of proportionality

y = k × x

27 = k × 4

27 = 4k

k = 27/4

k = 6.75

Find y when x = 12

y = k × x

y = 6.75 × 12

y = 81

Therefore, the value of y when x = 12 is 81

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