oblivionmoonstone
Answered

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The code to perform a binary search is below. Match the variable name with what it holds.

first = 0
last = len(data) - 1
done = False
numberPasses = 0 while first <= last and not done:
middle = (first + last) // 2
numberPasses =
numberPasses + 1
if data[middle] == 10:
done = True
else:
if data[middle] > 10:
last = middle - 1
else:
first = middle + 1

(This is a matching thing and the terms last, middle, and first are supposed to be matched in order to the options below I’ll give branliest!!)

-the index of the center item in the list being considered
-the index of the rightmost member of the list being considered
-the index of the leftmost member of the list being considered

Sagot :

mikaagsaoaypacheco

Answer:

First - The index of the leftmost member of the list being considered

Middle - The index of the center item in the list being considered

Last - The index of the rightmost member of the list being considered

Explanation:

Got it right on EDG. Sorry if I'm a little late but have a good day!

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