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Sagot :
The square footage of the path is 47.1 ft²
The area of a circle is:
A = πr²
Where r is the radius of the circle.
Let us assume that the pool is a circle.
Given that the pool has a radius (r₁) of 7 feet and a path 1 foot wide would go round the pool.
Radius of pool and cement path (r₂) = 7 ft + 1 ft = 8 ft.
The square footage of the path = πr₂² - πr₁² = π*8² - π * 7² = 47.1 ft²
Hence The square footage of the path is 47.1 ft²
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