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Ada, Betty, Chris and David have $45 in total Ada gota 52 fromBetty, Chris tripleshis money and Davids money is cut by hall four of them have the same amount. Initially Ada has?​

Sagot :

Using a system of equations, it is found that initially Ada has $0.385.

For the system, we have that the variables are:

  • x is Ada's amount.
  • y is Betty's amount.
  • z is Chris's amount.
  • w is David's amount.

$45 total, hence:

[tex]x + y + z + w = 45[/tex]

Ada gets 2 from Betty, hence:

[tex]x + 2 = y - 2[/tex]

[tex]x = y - 4[/tex]

[tex]y = x + 4[/tex]

Chris triples his money and David's money is cut by half four of them have the same amount, hence:

[tex]x + 4 = y = 3z = \frac{w}{2}[/tex]

Then:

[tex]3z = x + 4[/tex]

[tex]z = \frac{x + 4}{3}[/tex]

[tex]x + 4 = \frac{w}{2}[/tex]

[tex]w = 2x + 8[/tex]

Solving for w, we find Ada's initial amount.

[tex]x + y + z + w = 45[/tex]

[tex]x + x + 4 + \frac{x + 4}{3} + 2x + 8 = 45[/tex]

[tex]4x + 12 + \frac{x + 4}{3} = 45[/tex]

[tex]12x + 36 + x + 4 = 45[/tex]

[tex]13x = 5[/tex]

[tex]x = \frac{5}{13}[/tex]

[tex]x = 0.385[/tex]

Initially, Ada has $0.385.

A similar problem is given at https://brainly.com/question/6120515