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Sagot :
The equation of the line which is parallel to the line given is; 3y -x = -12
The slope of the line 3y-x=-12 can be evaluated by rearranging the equation to resemble the slope-intercept form of a linear equation as follows;
- y = (1/3)x -12
The slope of the line is therefore; 1/3;
However, the line parallel to it also has slope; 1/3.
Therefore, the equation of the line as requested is;
- 1/3 = (y -2)/(x -18)
By Cross-product;
- 3y -6 = x -18
The equation of the line is therefore;
- 3y -x = -12.
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