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Rent-An-SUV charges an $80 fee to rent a truck and $12 per mile. Another rental company charges a $150 fee to rent a truck
and $8.50 per mile.

Sagot :

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The linear equation that can be used to calculate daily car rentals is f(x) = -20x + 320

Since we are not told what to find, we can look for the linear equation that can be used to calculate daily car rentals;

  • Let the charge amount be y
  • Let the amount per mile of the truck rent be x.

  • If rent-An-SUV charges an $80 fee to rent a truck and $12 per mile, this can be expressed in coordinate form as (12, 80)

  • Similarly, if another rental company charges a $150 fee to rent a truck and $8.50 per mile, this can also be written in a coordinate form as (8.50, 150)

The standard linear expression is given as f(x) = mx + b

  • m is the rate of change
  • b is the y- intercept

Get the rate of change;

[tex]m=\frac{150-80}{8.5-12}\\m=\frac{70}{-3.5}\\m= -20\\[/tex]

Get the y-intercept;

80 =  -20(12) + b

80 = -240 + b

b = 320

Get the required linear equation;

f(x) = mx + b

f(x) = -20x + 320

Hence the linear equation that can be used to calculate daily car rentals is f(x) = -20x + 320

Learn more on linear equation here: https://brainly.com/question/12788590

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