At Westonci.ca, we connect you with the best answers from a community of experienced and knowledgeable individuals. Our platform offers a seamless experience for finding reliable answers from a network of experienced professionals. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.
Sagot :
The linear equation that can be used to calculate daily car rentals is f(x) = -20x + 320
Since we are not told what to find, we can look for the linear equation that can be used to calculate daily car rentals;
- Let the charge amount be y
- Let the amount per mile of the truck rent be x.
- If rent-An-SUV charges an $80 fee to rent a truck and $12 per mile, this can be expressed in coordinate form as (12, 80)
- Similarly, if another rental company charges a $150 fee to rent a truck and $8.50 per mile, this can also be written in a coordinate form as (8.50, 150)
The standard linear expression is given as f(x) = mx + b
- m is the rate of change
- b is the y- intercept
Get the rate of change;
[tex]m=\frac{150-80}{8.5-12}\\m=\frac{70}{-3.5}\\m= -20\\[/tex]
Get the y-intercept;
80 = -20(12) + b
80 = -240 + b
b = 320
Get the required linear equation;
f(x) = mx + b
f(x) = -20x + 320
Hence the linear equation that can be used to calculate daily car rentals is f(x) = -20x + 320
Learn more on linear equation here: https://brainly.com/question/12788590
We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. We're dedicated to helping you find the answers you need at Westonci.ca. Don't hesitate to return for more.