Answered

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A 65kg swimmer pushes off the pool wall and accelerates at 6m/s2. The friction experienced by the swimmer is 100n. What is the magnitude of the force that the swimmer applies on the wall?.

Sagot :

Answer:

490 N

Explanation:

Fnet = ma

       = 65*6

       = 390 N

Net force is applied force (Fapp) and friction force (Ff) in the opposite direction.

Fnet= Fapp - Ff

390=x-100

x=490N

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