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Write a linear equation that passes through the given two points.

(0, 1) and (5,3)

Sagot :

Y= 2/5x +1

Using the first point, you find the Y-intercept (y=mx+1)

Then plug the coordinates into the equation y2-y1/x2-x1

(y=2/5x+1). Hope this helps :))

Answer:

y = [tex]\frac{2}{5}[/tex] x + 1

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]

with (x₁, y₁ ) = (0, 1 ) and (x₂, y₂ ) = (5, 3 )

m = [tex]\frac{3-1}{5-0}[/tex] = [tex]\frac{2}{5}[/tex]

The line crosses the y- axis at (0, 1 ) ⇒ c = 1

y = [tex]\frac{2}{5}[/tex] x + 1 ← equation of line