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Write an equation of a line that is perpendicular to y=-2x+6 and passes through (-4,7)

Sagot :

Answer: y= x/2+9

Step-by-step explanation:

The equation of the line in the slope-intercept form is y=6−2x.

The slope of the perpendicular line is negative inverse: m=1/2.

So, the equation of the perpendicular line is y=x/2+a.

To find a, we use the fact that the line should pass through the given point: 7=(1/2)⋅(−4)+a.

Thus, a=9.

Therefore, the equation of the line is y=x/2+9.

Answer: y=x/2+9.