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A 4600 kg helicopter accelerates upward at 2.0 m/s squared by the upward life (Fa) exerted by the air on the propellers. Assume that there is no air resistance.
Calculate the net force of helicopter using Newton's 2nd Law.
Calculate the helicopter's weight?
Calculate the lift-force (Fa) exerted by the air on the propellers
Please I need the answers

Sagot :

onyebuchinnaji

(a) The net force upward force of the helicopter is -35,880 N.

(b) The weight of the helicopter is 45,080 N.

(c) The lift-force exerted by the air on the propellers is 9,200 N.

The given parameters:

  • mass of the helicopter, m = 4600 kg
  • acceleration of the helicopter, a = 2 m/s²

The net force upward force of the helicopter is calculated as follows;

[tex]F = ma - mg\\\\F = m(a - g)\\\\F = 4600(2 - 9.8)\\\\F = - 35,880 \ N[/tex]

The weight of the helicopter is calculated as follows;

[tex]W = mg\\\\W = 4600 \times 9.8\\\\W = 45,080 \ N[/tex]

The lift-force exerted by the air on the propellers is calculated as follows;

[tex]F = ma\\\\F = 4600 \times 2\\\\F = 9,200 \ N[/tex]

Learn more about Newton's 2nd Law here: https://brainly.com/question/3999427

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