Answered

Welcome to Westonci.ca, your go-to destination for finding answers to all your questions. Join our expert community today! Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.

18. A rock is thrown straight upward with an initial velocity of 12.2 m/s from a location where the acceleration due to gravity is 9.8 m/s2. How high up does it go

Sagot :

Eduard22sly

The height to which the rock can attain is 7.6 m

From the question given above, the following data were obtained:

Initial velocity (u) = 12.2 m/s

Acceleration due to gravity (g) = 9.8 m/s²

Final velocity (v) = 0 m/s (at maximum height)

Maximum height (h) =?

The maximum height to which the rock can attain can be obtained as follow:

v² = u² – 2gh (since the rock is going against gravity)

0² = 12.2² – (2 × 9.8 × h)

0 = 148.84 – 19.6h

Collect like terms

0 – 148.84 = – 19.6h

–148.84 = –19.6h

Divide both side by –19.6

h = –148.84 / –19.6

h = 7.6 m

Thus, the height to which the rock can attain is 7.6 m

Learn more: https://brainly.com/question/25711946

Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. We're glad you visited Westonci.ca. Return anytime for updated answers from our knowledgeable team.