Answered

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Find the equation of a line passing through (-3,-1) and (6,-7)

Sagot :

Answer:

Step-by-step explanation:

y = mx + b

m = Δy/Δx = (-1 - (-7)) / (-3 - 6) = 6/-9 = -2/3

y = (-2/3)x + b

-1 = (-2/3)(-3) + b

-1 = 2 + b

b = -3

y = (-2/3)x - 3

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