At Westonci.ca, we connect you with the best answers from a community of experienced and knowledgeable individuals. Experience the convenience of finding accurate answers to your questions from knowledgeable professionals on our platform. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.

Help please! I'm in Algebra class and I'm stuck on solving this tricky problem. I would be very grateful to anyone who could offer an answer.

Help Please Im In Algebra Class And Im Stuck On Solving This Tricky Problem I Would Be Very Grateful To Anyone Who Could Offer An Answer class=

Sagot :

Answer:

A. Which Sibling received the most money

(Sibling B)

the least money ? (Sibling A)

which Sibling spends money at the fastest rate?

(Sibling B)

the slowest rate?

(Sibling A)

which Sibling runs out of money first?

(Sibling C) and Last? (Sibling A)

Step By Step Explanation?

a. We can know from the graph. A received so dollars.

Assuming that B y=ax+b

100=a+b. a= -25

175 = 2a+b b=125

- B₁ y=-25x+125

:. B received 125 dollars.

C+ y = -22.5x +90 : C C received dollars.

125> 90 80

B received the most money. A received the least money.

b. Assuming that A: M= ax+b

$ 0= -15 40+b=20 1 b = 80 y=-15x+80

• Y₁ = -25x+125, Y₁ = -22.5 mx +90

1-151 <1-22.5) <1-251 {The steeper the slope, the steeper the line}

B spends money at the fastest rate

A spends money at the slowest rate.

C. MA=-15x + 80 when Y₁ = 0 . x = 15

Y₁ = -25x+125, when y₁=0₁ x = 12/5/² = 5 35

Y₁ = -22.5 x +9°, when y₁=0₁ x = 12/2²/5 = 4 9⁰

:: C runs out of money first

A runs out of money last

Answer:

1.B

2.A

3.B

4.A

5.C

6.A

Step-by-step explanation:

Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Westonci.ca is committed to providing accurate answers. Come back soon for more trustworthy information.