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A boat is heading towards a lighthouse, whose beacon-light is 115 feet above the water. The boat's crew measures the angle of elevation to the beacon , . What is the 6 degrees ship's horizontal distance from the lighthouse (and the shore)? Round your answer to the nearest hundredth of a foot if necessary .

Sagot :

Answer:

Step-by-step explanation:

Hundredth of a foot. Laughable request for precision when the angle is only a single significant digit and the height is only 3 s.d.

tan6 = opp/hyp = 115/x

x = 115/tan6

x = 1,094.151912...

x = 1,094.15 ft

to get that precision the angle and height should be reported as 6.00000° and 115.000 ft.

abidemiokin

The horizontal distance from the lighthouse is 1094.15feet

SOH CAH TOA identity

In order to get the required distance, we will use the SOH CAH TOA identity

tan6 = opp/hyp = 115/x

x = 115/tan6

x = 1,094.151912...

x = 1,094.15 ft

The horizontal distance from the lighthouse is 1094.15feet

Learn more on SOH CAH TOA identity here: https://brainly.com/question/20734777

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