nab34
Answered

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(x+3)^2=4

solve the following equation,giving your answer correct to 2 decimal places
where necessary


Sagot :

Answer:

x = -1, -5

Step-by-step explanation:

[tex] {(x + 3)}^{2} = 4 \\ = > {x}^{2} + 2 \times x \times 3 + {3}^{2} = 4 \\ = > {x}^{2} + 6x + 9 = 4 \\ = > {x}^{2} + 6x = 4 - 9 \\ = > {x}^{2} + 6x = - 5 \\ = > {x}^{2} + 6x + 5 = 0 \\ = > {x}^{2} + 5x + x + 5 = 0 \\ = > x(x + 5) + 1(x + 5) = 0 \\ = > (x + 1)(x + 5) \\ = > x = - 1 \: \: or \: \: - 5[/tex]

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Answer:

x= -1

Step-by-step explanation:

(x+3)^2=4

2x + 6 = 4

2x = 2

divide each term in 2x = -2 by 2 and simplify.

answer ( x = -1 )

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