Answered

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What is the equation of the line that passes through the point (-5,-2) and had a slope of -6/5

Sagot :

Answer:

y = -6/5x - 8

Step-by-step explanation:

Use the slope-intercept form y = mx + b and substitute slope(m) = -6/5 and the point (-5, -2). After that solve for b

y = mx + b

-2 = -6/5(-5) + b

-2 = 6 + b

-8 = b

For the equation  substitute into y = mx + b ;  y = -6/5x - 8

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