Westonci.ca offers quick and accurate answers to your questions. Join our community and get the insights you need today. Get expert answers to your questions quickly and accurately from our dedicated community of professionals. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.
Sagot :
The mass of HgO needed for the reaction is 216 g
The correct answer to the question is Option C. 216 g
We'll begin by calculating the theoretical yield of Hg.
- Actual yield of Hg = 100 g
- Percentage yield = 50%
- Theoretical yield of Hg =?
Theoretical yield = Actual yield / percentage yield
Theoretical yield = 100 / 50%
Theoretical yield of Hg = 200 g
Finally, we shall determine the mass of HgO needed for the reaction.
2HgO → 2Hg + O₂
Molar mass of HgO = 201 + 16 = 217 g/mol
Mass of HgO from the balanced equation = 2 × 217 = 434 g
Molar mass of Hg = 201 g/mol
Mass of Hg from the balanced equation = 2 × 201 = 402 g
From the balanced equation above,
402 g of Hg were produced from 434 g of HgO.
Therefore
200 g of Hg will be produce by = (200 × 434) / 402 = 216 g of HgO.
Thus, 216 g of HgO is needed for the reaction.
Learn more about stoichiometry:
https://brainly.com/question/24426334
Visit us again for up-to-date and reliable answers. We're always ready to assist you with your informational needs. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. We're glad you visited Westonci.ca. Return anytime for updated answers from our knowledgeable team.