Explore Westonci.ca, the leading Q&A site where experts provide accurate and helpful answers to all your questions. Get detailed and accurate answers to your questions from a community of experts on our comprehensive Q&A platform. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.
Sagot :
The mass of HgO needed for the reaction is 216 g
The correct answer to the question is Option C. 216 g
We'll begin by calculating the theoretical yield of Hg.
- Actual yield of Hg = 100 g
- Percentage yield = 50%
- Theoretical yield of Hg =?
Theoretical yield = Actual yield / percentage yield
Theoretical yield = 100 / 50%
Theoretical yield of Hg = 200 g
Finally, we shall determine the mass of HgO needed for the reaction.
2HgO → 2Hg + O₂
Molar mass of HgO = 201 + 16 = 217 g/mol
Mass of HgO from the balanced equation = 2 × 217 = 434 g
Molar mass of Hg = 201 g/mol
Mass of Hg from the balanced equation = 2 × 201 = 402 g
From the balanced equation above,
402 g of Hg were produced from 434 g of HgO.
Therefore
200 g of Hg will be produce by = (200 × 434) / 402 = 216 g of HgO.
Thus, 216 g of HgO is needed for the reaction.
Learn more about stoichiometry:
https://brainly.com/question/24426334
Thanks for using our service. We aim to provide the most accurate answers for all your queries. Visit us again for more insights. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Get the answers you need at Westonci.ca. Stay informed with our latest expert advice.