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Sagot :
Answer:
In right triangle hypotenus(side facing angle 90)is the longest
Step-by-step explanation:
lets say hyp=side1 +side2 were(side1=side2 in isocseles..) and Let x bet the length of side 1
So by applying phythegoras theorem :
hyp^2=x^2+x^2
16^2 =2x^2
2x^2=256
x^2=128
[tex] \sqrt{x { }^{2} } = \sqrt{128} [/tex]
x=
[tex]8 \sqrt{2} [/tex]
Parameter=16+8
[tex]8 \sqrt{2 } + 8 \sqrt{2 } + 16[/tex]
[tex]16 \sqrt{2} + 16[/tex]
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