Answered

Westonci.ca is the premier destination for reliable answers to your questions, provided by a community of experts. Connect with a community of experts ready to help you find solutions to your questions quickly and accurately. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.

A 5 kg box is lying at rest on a frictionless surface. If you push it with a constant net force of 10 N, how far will it travel over the first 4 s

Sagot :

asuwafohjames

The distance traveled by the box over the first 4 s  is 16 m.

To solve the problem above,  First, we apply newton's Fundamental equation of force.

Newton's fundamental equation of force:

F = ma...................... Equation 1

Where

  • F = Force
  • m = mass of the box
  • a = acceleration

make "a " the subject of the equation

a = F/m...................... Equation 2

From the question,

Given:

  • F = 10 N
  • m = 5 kg

Substitute these values into equation 2

a = 10/5

a = 2 m/s²

Finally, we use the equation of motion to calculate the distance it will travel over the given period of time.

Equation of motion

s = ut+at²/2........................... Equation 3

Where:

  • s = total distance traveled
  • t = time
  • u = initial velocity

Given:

  • t = 4 s
  • u = 0 m/s (at rest)
  • a = 2 m/s²

Substitute these values into equation 3

  • s = 0(4)+(2×4²)/2
  • s = 0+32/2
  • s = 16 m

Hence, the distance traveled by the box over the first 4 s  is 16 m

Learn more about Newton's fundamental equation here: https://brainly.com/question/13370981

We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Find reliable answers at Westonci.ca. Visit us again for the latest updates and expert advice.