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Solve the following equation (x-4)^2=7

Sagot :

loneguy

[tex](x-4)^2 =7\\\\\implies x-4 = \pm \sqrt 7\\\\\implies x = 4 \pm \sqrt 7\\\\\ \text{Hence,}~ x =4 + \sqrt 7~~ \text{or}~~x =4 -\sqrt 7[/tex]

silirobert15

[tex](x-4) ^ 2 = 7 => | x-4 | = \sqrt{7} \\=> x-4=\sqrt{7} / or/ x-4=-\sqrt{7}\\ => x=\sqrt{7} + 4 /or/ x = 4-\sqrt{7}[/tex]

ok done. Thank to me :>

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