The percent yield of the product is 83.20% if the beaker weighs 10.20 g, the dry substance in the beaker weighs 16.54 g, and the expected mass is 7.62 g.
The percent yield of the product is given by:
[tex] \% = \frac{m_{e}}{m_{t}} \times 100 [/tex]
Where:
[tex] m_{e}[/tex]: is the experimental mass
[tex] m_{t}[/tex]: is the theoretical mass = 7.62 g
We can obtain the experimental mass by substrating the mass of the beaker from the mass of the dry substance in the beaker.
[tex] m_{e} = (16.54 - 10.20) g = 6.34 g [/tex]
Hence, the percent yield is:
[tex] \% = \frac{6.34}{7.62} \times 100 = 83.20 \% [/tex]
Therefore, the percent yield of the product is 83.20%.
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