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An arrow of mass 20 g is shot horizontally into a bale of hay, striking the hay with a velocity of 60 m/s. It penetrates a depth of 40 cm before stopping. What is the average stopping force acting on the arrow

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From the question, The kinetic energy of the fired arrow is equal to the work done by the bale of hale in stopping the arrow.

We make use of the following formula

mv²/2 = F'd................... Equation 1

Where

  • m = mass of the arrow
  • v = velocity of the arrow
  • F' = average stopping force acting on the arrow
  • d = distance of penetration

Make F' the subject of the equation

F' = mv²/2d.................. Equation 2

From the question,

Given:

  • m = 20 g = 0.02 kg
  • v = 60 m/s
  • d = 40 cm = 0.4 m

Substitute these values into equation 2

  • F' = 0.02(60²)/(0.4×2)
  • F' = 72/0.8
  • F' = 90 N

Hence, The average stopping force acting on the arrow is 90 N

Learn more about average stooping force here: https://brainly.com/question/13370981

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