Westonci.ca is the best place to get answers to your questions, provided by a community of experienced and knowledgeable experts. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.
Sagot :
The amount of the unstable isotope that will remain after 6 days is 205 Kg
We'll begin by calculating the the number of half-lives that has elapsed
Half-life (t½) = 3 days
Time (t) = 6 days
Number of half-lives (n) =?
n = t / t(½)
n = 6 / 3
n = 2
Thue, 2 half-lives has elapsed
- Finally, we shall determine the amount remaining.
Number of half-lives (n) = 2
Original amount (N₀) = 820 Kg
Amount remaining (N) =?
N = 1/2ⁿ × N₀
N = 1/2² × 820
N = 1/4 × 820
N = 0.25 × 820
N = 205 Kg
Thus, 205 Kg of the unstable isotope will remain after 6 days
Learn more: https://brainly.com/question/25749387
Thanks for using our service. We aim to provide the most accurate answers for all your queries. Visit us again for more insights. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Get the answers you need at Westonci.ca. Stay informed with our latest expert advice.