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a box of 5kg is lifted 10m. how much work is done?

Sagot :

evgeniylevi

Answer:

500 [J].

Explanation:

1) the rule is: W=E₂-E₁, where W - required work, E₂ - energy after lifting, E₁ - energy before lifting;

2) energy: E=mgh, where m - mass, g≈10 [N/kg], h - height;

3) then the required work:

W=mgh₂-mgh₁=m*g*(h₂-h₁), where (h₂-h₁)=10 [m.]

finally, W=5*10*10=500 [J].

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