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Calculate the root mean square velocity and kinetic energy of F2, Cl2 and Br2 at 298 K. Rank these three halogens with respect to their rate of effusion.

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The ranking of the three halogens with respect to their rate of effusion:

Fluorine (F₂) > Chlorine (Cl₂) > Bromine (Br₂)

The given parameters;

  • fluorine gas, F₂
  • chlorine gas, Cl₂
  • Bromine, Br₂

The molecular mass of the three halogens is calculated as follows;

[tex]F_2 = 2(19) = 38 \ g/mol = 38 \times 10^{-3} \ kg/mol\\\\Cl_2 = s(35.5) = 71 \ g/mol = 71 \times 10^{-3} \ kg/mol\\\\Br_2 = 2(80) = 160 \ g/mol = 160 \times 10^{-3} \ kg/mol[/tex]

The speed of three halogens is calculated as follows;

[tex]v = \sqrt{\frac{3RT}{M} } \\\\v_{F_2}= \sqrt{\frac{3 \times 8.314 \times 298}{38 \times 10^{-3} } } \ = 442.26 \ m/s\\\\v_{Cl_2}= \sqrt{\frac{3 \times 8.314 \times 298}{71 \times 10^{-3} } } \ = 323.55 \ m/s\\\\v_{Br_2}= \sqrt{\frac{3 \times 8.314 \times 298}{160 \times 10^{-3} } } \ =215.53 \ m/s[/tex]

The ranking of the three halogens with respect to their rate of effusion:

Fluorine (F₂) > Chlorine (Cl₂) > Bromine (Br₂).

Learn more about rate of effusion of gases here: https://brainly.com/question/13547979

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