Explore Westonci.ca, the premier Q&A site that helps you find precise answers to your questions, no matter the topic. Explore our Q&A platform to find reliable answers from a wide range of experts in different fields. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.
Sagot :
The dimensions of the image are twice the dimensions of the preimage,
which indicates that the transformation is a dilation.
- The transformation T is; a dilation transformation with a scale factor of 2, D₂
Reasons:
The transformation applied to ΔABC = T
The image of ΔABC following the transformation, T = ΔA'B'C'
The perimeter of ΔA'B'C' = Twice the perimeter of ΔABC
Therefore, we have;
A'B' + B'C' + A'C' = 2 × (AB + BC + AC)
Which gives
A'B' + B'C' + A'C' = 2·AB + 2·BC + 2·AC
By similar triangles, we have the ratio of corresponding sides as follows;
[tex]\displaystyle \frac{AB}{A'B'} = \frac{BC}{B'C'} = \mathbf{ \frac{AC}{A'C'}}[/tex]
Which gives;
[tex]\displaystyle \frac{AB}{A'B'} = \frac{AB}{2 \cdot AB} = \frac{1}{2}[/tex]
A'B' = 2·AB
Therefore;
- Triangle ΔA'B'C' is twice the dimension of triangle ΔABC, and T is a dilation transformation with a scale factor of 2, D₂
Learn more about dilation transformation here:
https://brainly.com/question/2458912
We appreciate your visit. Hopefully, the answers you found were beneficial. Don't hesitate to come back for more information. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Your questions are important to us at Westonci.ca. Visit again for expert answers and reliable information.
